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A circular sector or circle sector (symbol: ⌔), is the portion of a disk enclosed by two radii and an arc, where the smaller area is known as the minor sector and the larger being the major sector. [1] : 234 In the diagram, θ is the central angle , r {\displaystyle r} the radius of the circle, and L {\displaystyle L} is the arc length of the minor sector. Now, a quadrant is one-fourth section of a circle which is obtained when a circle is divided evenly into four sections or rather 4 quadrants by a set of two lines which are perpendicular in nature. In this article, let us discuss what a quadrant is, how to calculate the area of the quadrant with examples in detail.
If ABE is a quadrant of a circle find the area of the shaded region. Q.15 In figure , ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region. Sol. Let 14 cm be the radius of the quadrant with A as the centre. Then the area of the quadrant ABMC RD Sharma Class 10 Solutions Areas related to Circles Ex 15.4 RD Sharma Class 10 Solutions Areas related to Circles Exercise 15.4 Question 1.
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Find the area of the shaded region. Fig. 12.33 from Mathematics Areas Related to Circles Class 10 Meghalaya Board Areas Related to Circles In right angled triangle ABC,we haveAC 2 =AB2 +BC 2AC 2 =142 +142AC = 2×142 = 14 2 cmNow required Area=Area AP C QA=Area AC QA - Area AC P A=Area AC QA - (Area ABC P A - Area of Δ ABC)= 21 ×π×( 214 2 )2 −[41 ×π(14)2 − 21 ×14×14]= 21 × 722 ×7 2 ×7 2 − 41 × 722 ×14×14+ 21 ×14×14= 154−154+98= 98 cm2. If ABE is a quadrant of a circle, find the area of the shaded region. Take π = 22 7 Area of a trapezium = 24 .
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Calculus "A rectangle is inscribed in a semicircle of radius 2 cm. Find the largest area of such a rectangle". There is a diagram, but I think the question makes it clear enough what is going on. 4 Jun 2014 in fig abc is a quadrant of a circle of radius 14 cm and a semi circle is drawn with bc as diameter find the area of shaded region - Mathematics Q29 In the given figure ABCD represent the quadrant of a circle of radius 7 cm with centre A. Calculate the area of the shaded region. [Take π = 22/7.] Find the area of a quadrant of a circle whose circumference is 22 cm. region in figure, if ABCD is a square of side 14 cm and APD and BPC are semi-circles. Find the area of a quadrant of circle whose circumference is 22 cm.
They are at 0,90,180,270 of the current UCS ---WHEN THE CIRCLE WAS DRAWN--- meaning that if you change the UCS, the quadrant points do not change with it they remain where they were before. From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in the given figure. Find the area of the remaining portion of the square.
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A quadrant of a circle of radius 1 cm is drawn at each vertex of the square and a circle of diameter 2 cm is also drawn. Find the area of the shaded region. [π = 3.14] Advertisement Remove all ads In figure, ABCD is a square of side 4 cm. A quadrant of a circle of radius 1 cm is drawn at each vertex of the square and a circle of diameter 2 cm is also drawn. Find the area of the shaded region ABCD is a quadrent of a circle of radius 28cm, and a semicircle BEC is drawn with BC as diameter.
Find the area of the shaded region. [π = 3.14] Advertisement Remove all ads
In figure, ABCD is a square of side 4 cm. A quadrant of a circle of radius 1 cm is drawn at each vertex of the square and a circle of diameter 2 cm is also drawn. Find the area of the shaded region
ABCD is a quadrent of a circle of radius 28cm, and a semicircle BEC is drawn with BC as diameter.
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2018-08-02 2018-05-29 In the figure ABCD is a quadrant of a circle of radius 2 8 cm and a semi circle BEC is drawn with BC as diameter . Find the area of the shaded region.( Use π = 7 2 2 ) Answer with step by step detailed solutions to question from 's , Polynomials- "In Figure 5, ABCD is a quadrant of a circleof radius 28 cm and a semi circle BEC is The area of an equilateral triangle ABC is 17320.5 cm2 . With each vertex of the triangle as centre, a circle is drawn with radius equal to half the length of the side of the triangle (see Fig. 12.28). Find the area of the shaded region (Use = 3.14 and 1.73205) Fig. 12.28 ABDC is a quadrant of a circle of radius 28 cm and a semi-circle BEC is drawn with BC as diameter.
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2018-08-02 2018-05-29 In the figure ABCD is a quadrant of a circle of radius 2 8 cm and a semi circle BEC is drawn with BC as diameter . Find the area of the shaded region.( Use π = 7 2 2 ) Answer with step by step detailed solutions to question from 's , Polynomials- "In Figure 5, ABCD is a quadrant of a circleof radius 28 cm and a semi circle BEC is The area of an equilateral triangle ABC is 17320.5 cm2 . With each vertex of the triangle as centre, a circle is drawn with radius equal to half the length of the side of the triangle (see Fig. 12.28).
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Perimeter of a quadrant = ((Π/ Notice that ¯AE=¯EB=¯AB=14 because they are all radii of the circle. The points A, B and E In the given figure, ABCD is a square of side 10 cm and semicircles are. play ABCP is a quadrant of a circle of radius 14 cm.